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Q30 / Preparation & verification / question

What limits STP preparation of accepted quantum witnesses?

Bound the STP cost of preparing a state close to an accepted witness, with explicit trace-distance error and success probability.

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Working mathematical formulation

Fix a uniform family of STP verifiers VxV_x, a witness encoding, a polynomial register bound, and a completeness/soundness gap. For YES instances let AxA_x be the set of states accepted above the completeness threshold. What is the minimum expected STP preparation cost, from mixed inputs with declared ancillas, of preparing a state within trace distance ε\varepsilon of some member of AxA_x, conditioned on a specified set of measurement outcomes with total probability at least pp? Can subsystem-spin or multiplicity structure bound this cost while keeping verification polynomial?

Scope & assumptions

An unrelativized lower bound separating efficient preparation from all quantum algorithms can depend on unresolved complexity assumptions. State such assumptions, or prove a restricted-model or oracle result. Easy preparation of singlets or coupling-tree states does not establish efficient preparation of arbitrary witnesses.

Why this is interesting

The distinction is between states useful for BQP\mathsf{BQP} computation and QMA\mathsf{QMA} witnesses. Testing local spin structure need not give a method to prepare an accepted global state.

A place to start

Begin with the randomized-edge verifier in Q15. Separate preparation of any accepted witness from preparation of one prescribed ground state, then ask which spin data gives a lower bound or a constructive preparation procedure.

Related work

These works provide context and established results. They need not be the origin of this exact formulation.

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