What limits STP preparation of accepted quantum witnesses?
Bound the STP cost of preparing a state close to an accepted witness, with explicit trace-distance error and success probability.
Discuss this questionFix a uniform family of STP verifiers , a witness encoding, a polynomial register bound, and a completeness/soundness gap. For YES instances let be the set of states accepted above the completeness threshold. What is the minimum expected STP preparation cost, from mixed inputs with declared ancillas, of preparing a state within trace distance of some member of , conditioned on a specified set of measurement outcomes with total probability at least ? Can subsystem-spin or multiplicity structure bound this cost while keeping verification polynomial?
An unrelativized lower bound separating efficient preparation from all quantum algorithms can depend on unresolved complexity assumptions. State such assumptions, or prove a restricted-model or oracle result. Easy preparation of singlets or coupling-tree states does not establish efficient preparation of arbitrary witnesses.
Why this is interesting
The distinction is between states useful for computation and witnesses. Testing local spin structure need not give a method to prepare an accepted global state.
A place to start
Begin with the randomized-edge verifier in Q15. Separate preparation of any accepted witness from preparation of one prescribed ground state, then ask which spin data gives a lower bound or a constructive preparation procedure.
Related work
These works provide context and established results. They need not be the origin of this exact formulation.
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